string constant mangling
David Vandevoorde
daveed at edg.com
Tue Mar 8 21:12:49 UTC 2011
On Mar 8, 2011, at 11:43 AM, Jason Merrill wrote:
> On 07/14/2010 10:56 AM, David Vandevoorde wrote:
>> On Jul 13, 2010, at 10:08 PM, John McCall wrote:
>>> On Jun 30, 2010, at 8:33 AM, David Vandevoorde wrote:
>>>> - We propose additional encodings for literals that can now appear in signatures. nullptr is "LDn0E"; i.e., "a zero of type std::nullptr_t". More interestingly, string literals are encoded as L<character type>E, where<character type> is the encoding of the (unqualified) underlying character type. This has a few consequences for the demangler: It cannot actually reproduce the string, and it can only distinguish character literals from string literals after having seen the first character following the character type code.
>>>
>>> Is this sufficient? Overloading can be dependent on the length of the string, i.e. these are different templates:
>>> template<class T> auto foo(T x) -> decltype(bar(x, "abc"));
>>> template<class T> auto foo(T x) -> decltype(bar(x, "abcd"));
>>
>> Good catch!
>>
>> How about using:
>>
>> L<string type> E
>>
>> ?
>>
>> That matches the (new) nullptr approach. In addition to the string size, it also encodes the cv-qualifier, which ensures that we get distinct encodings for compilations with a mode where string literals are non-const.
>
> It occurs to me that now with constexpr, string constants can appear in a constant expression:
>
> template <typename T> constexpr T f(const T* p) { return p[0]; }
> template<int> struct N { };
> template <typename T> N<f((const T*)"1")> g(T);
> template <typename T> N<f((const T*)"2")> g(T);
>
> Here the two 'g's are different templates.
Ouch :-( I guess another tweak is needed then.
Daveed
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